Answer:
At a greater value of pH, [H⁺] is really low.
Solution with pH = 8 has more [H⁺] than solution at pH =12.
Explanation:
pH = - log [H⁺]
10^-pH = [H⁺]
At pH = 8, [H⁺] = 10⁻⁸ → 1×10⁻⁸ M
At pH = 12, [H⁺] = 10⁻¹² → 1×10⁻¹² M
In conclussion, at a greater value of pH, [H⁺] will be really low.
Solution with pH = 8 has more [H⁺] than solution at pH =12.
