eeezzzyyyy
eeezzzyyyy
19-04-2018
Mathematics
contestada
x^2-8x+a=0 the perfect square
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Cowmilk
Cowmilk
25-04-2018
[tex]( { \frac{b}{2}) }^{2} = a \\ ( { \frac{ - 8}{2} )}^{2} \\ {( - 4)}^{2} \\ 16 = a\\ \\ {x}^{2} - 8x + 16 = 0 \\ (x - 4)(x - 4) = 0 \\ x - 4 = 0 \\ x = 4[/tex]
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