First of all, your second line would have the same slope : 3
Then we know that this line passes throught the point (2, -4)
The equation for this line is like : [tex]y'=mx+p'[/tex]
[tex]y'=-4\\m=3\\x=2\\\\-4=3\times(2)+p\\-4=6+p\\p=-4-6\\p=-10\\[/tex]
So the equation in slope form for the line parallel to y = 3x+7 is : y' = 3x - 10
