jamalsanchez6498 jamalsanchez6498
  • 18-04-2018
  • Mathematics
contestada

Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds?

Respuesta :

ali015
ali015 ali015
  • 18-04-2018
Answer: 0J

The equation for work is W=Fdcos(x), where w=work, f=force, d=displacement, and x=angle the force makes with the displacement vector.

Since the man is holding a barbell and the object, the barbell, isn't being displaced, d=0, making the work done equal to zero.
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