courtneys1
courtneys1 courtneys1
  • 17-12-2015
  • Mathematics
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Multiply the bottom h's.
\frac{6h ^{2} }{2h ^{8}h h}

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TSO
TSO TSO
  • 20-12-2015
[tex]\frac{6h ^{2} }{2h ^{8}h h}= = \frac{6h^2}{2h^8h^2} = \frac{6h^2}{2h^{10}} = \frac{3h^2}{h^{10}} = \frac{3}{h^8} = \boxed{\boxed{\bf{3h^{-8}}}}[/tex]
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