aaronmono86
aaronmono86
19-01-2018
Mathematics
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find the 7th term of (x+y)^8
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LammettHash
LammettHash
19-01-2018
By the binomial theorem, we have
[tex](x+y)^8=\displaystyle\sum_{k=0}^8\binom8kx^{8-k}y^k[/tex]
where [tex]\dbinom8k=\dfrac{8!}{k!(8-k)!}[/tex]. The 7th term occurs when [tex]k=6[/tex], which gives
[tex]\dbinom86x^{8-6}y^6=28x^2y^6[/tex]
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