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  • 18-11-2015
  • Mathematics
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what's the perimeter of 80 and115l

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taskmasters
taskmasters taskmasters
  • 18-11-2015
P=2 (l+w)
P= 2 (80 + 1151)
P= 2 (1231)
P= 2462


The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle.   Since the geometric formula for perimeter is: 

P= 2 (l + w) 
L = 2w – 4 cm 
W =?   
Derivation and solution: 
34 = 2 (2w - 4) + 2w 
34 =  4w – 8 + 2w
 
42 = 6w 42/6 = w 
W = 7 cm   

34 = 2l + 2(7) 
34 = 2l + 14 
2l = 34 – 14 
2l = 20 
L = 20/2 
L = 10 cm   

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