Answer:
The radius of circle L is [tex]7.8\ in[/tex]
Step-by-step explanation:
we know that
In the figure the triangle VLM is a right triangle, because VL is pependicular to YM
so
[tex]YV=VM=12/2=6\ in[/tex]
LM is the radius of the circle (hypotenuse of triangle VLM)
[tex]VL=5\ in[/tex]
Applying the Pythagoras Theorem
[tex]LM^{2}=VM^{2}+VL^{2}[/tex]
substitute
[tex]LM^{2}=6^{2}+5^{2}[/tex]
[tex]LM^{2}=61[/tex]
[tex]LM=7.8\ in[/tex] ------> is the radius
