Respuesta :
Kinetic energy of freely falling ball = [tex] \frac{mv^{2} }{2} [/tex]
∴ velocity of ball = √(2×K.E/m) = √(200/2) = 10 m/s.
∴ velocity of ball = √(2×K.E/m) = √(200/2) = 10 m/s.