Lindsay882
Lindsay882
19-11-2017
Mathematics
contestada
simplify completely.
[tex] \sqrt{68} [/tex]
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jdoe0001
jdoe0001
19-11-2017
[tex]\bf \sqrt{68}\qquad \begin{cases} 68=2\cdot 2\cdot 17\\ \qquad 2^2\cdot 17 \end{cases}\qquad \sqrt{2^2\cdot 17}\implies 2\sqrt{17}[/tex]
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