y = –6.x² + 3.x + 2.
Its vertex form is (y-k) = a(x-h)², where the vertex is V(h , k).
Let's calculate k and h from the original function y = - 6.x² + 3.x + 2.
a) the maximum is when f(0) = k→ -6(0)² + 3(0) + 2 , hence k = 2
b) The axis of symmetry is equal to x = -b/2.a:
x= -(3)/2.(-6) → x = 1/4 (1/4 is = h); Now replace k & h in the Vertex form
y-k = a(x-h)²
y- 2 = -6(x-1/4)²
