16-09-2015
Mathematics

contestada

how do I convert

3[tex] x^{2} [/tex] - 20x - 7 = 0

into the form it was before distribution:

( ) ( ) = 0

Respuesta :

konrad509 konrad509

16-09-2015

[tex]3x^2-20x-7=0\\ 3x^2+x-21x-7=0\\ x(3x+1)-7(3x+1)=0\\ (x-7)(3x+1)=0\\ x=7 \vee x=-\dfrac{1}{3} [/tex]

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