kiwimelon14 kiwimelon14

19-09-2017
Mathematics

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(3a^2-3b)(2a^2+3b) find the product

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choixongdong choixongdong

19-09-2017

(3a^2-3b)(2a^2+3b)
= 6a^4 + 9a^2b - 6a^2b - 9b^2
= 6a^4 + 3a^2b - 9b^2

hope it helps

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