Let the first integer be represented by: 2k
the second integer by: 2(k+1)
and the third by: 2(k+2)
Then, 2k + 2(k+1) = 2(k+2) + 30
2k + 2k + 2 = 2k + 4 + 30
4k + 2 = 2k + 34
2k = 32
k = 16
first integer: 2k = 2(16) = 32
second integer: 2(k+1) = 2(16+1) = 2(17) = 34
third integer: 2(k+2) = 2(16+2) = 2(18) = 36
Answer: 32, 34, 36
