diamondslayer7
diamondslayer7 diamondslayer7
  • 18-08-2017
  • Mathematics
contestada

Solve The Geometry Question In The Image

Solve The Geometry Question In The Image class=

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apologiabiology
apologiabiology apologiabiology
  • 18-08-2017

use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²

we need AD and DC

so
AD²+7.9²=9.4²
AD=√25.95

DC²+7.9²=23.2²
DC=√475.83

so
AD+DC=base=(√25.95)+(√475.83)≈26.9076

AC≈26.91 units
Answer Link
Banabanana
Banabanana Banabanana
  • 20-08-2017
By the Pythagorean theorem:

[tex]AD= \sqrt{AB^2-BD^2}= \sqrt{9.4^2-7.9^2}= \sqrt{25.95} \approx 5.09 \ units\\\\ CD= \sqrt{BC^2-BD^2}= \sqrt{23.2^2-7.9^2}= \sqrt{475.83} \approx 21.81 \ units \\ \\ AC=AD+CD=5.09+21.81=26.9 \ units[/tex]
Answer Link

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