Rayzamartinez4211 Rayzamartinez4211
  • 18-06-2017
  • Chemistry
contestada

Xenon tetrafluoride gas is placed in a 3 liter container at 80°c. the pressure of the gas is found to be 0.117 atm. how many moles of the gas are in the container

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budwilkins
budwilkins budwilkins
  • 18-06-2017
PV = nRT --> n = PV/RT
n = (3)(.117)/(.0821)(353)
n = .351/28.98 = 0.0121 moles XeF4
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Annainn Annainn
  • 20-07-2019

Answer:

Moles of Xenon present = 0.012

Explanation:

Given:

Volume of container, V = 3.0 L

Temperature of Xe gas, T = 80 C

Pressure of Xe gas, P = 0.117 atm

To determine:

The moles of Xe gas

Explanation:

Based on the ideal gas equation:

[tex]PV = nRT[/tex]

where n = number of moles of the gas

R = gas constant = 0.0821 L.atm/mol-K

[tex]n = \frac{PV}{RT} = \frac{0.117atm*3.0 L}{0.0821 Latm/mol-K*(80+273)K} =0.012\ moles[/tex]

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