16-05-2017
Mathematics

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In rhombus fmkw mk=12 fk= 16 m

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FadaKen FadaKen

16-05-2017

If it is area your looking for.

Area = product of diagonal lengths divided by 2

Area = 12* 16 /2

=192/2 = 96.

IF it is the side length of the rhombus:

apply Pythagoras theorem since the diagonals always meet at 90°.

L =√(12² + 16²)

L= √400 = 20

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