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Given the balanced equation representing a reaction: 4nh3 + 5o2 4no + 6h2o what is the minimum number of moles of o2 that are needed to completely react with 16 moles of nh3?

Respuesta :

theleangreenbean

Key Concepts

  • Mole ratios
  • Limiting reagent
  • Balancing chemical equations

Solution

[tex]4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O[/tex]

We're given:

  • [tex]n(NH_3)=16\hspace{4}mol[/tex]
  • [tex]n(O_2)=?[/tex]

The mole ratio between NH3 and O2 is 4:5, meaning...

[tex]\dfrac{n(NH_3)}{4}=\dfrac{n(O_2)}{5}[/tex]

Plug in the given moles of NH3 and solve for moles of O2:

[tex]\dfrac{16}{4}=\dfrac{n(O_2)}{5}[/tex]

[tex]n(O_2)=20[/tex]

Answer

20 moles of O2 are needed to completely react with 16 moles of NH3.

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