Need help will do anything plzzzzz!!

Use the substitution method.

{j+k=3
{j-k=7
There are an infinite number of solutions.

There is no solution.

The solution is (5, −2).

The solution is (8, 1).

Question

21-03-2017
Mathematics

contestada

Need help will do anything plzzzzz!!

Use the substitution method.

{j+k=3
{j-k=7
There are an infinite number of solutions.

There is no solution.

The solution is (5, −2).

The solution is (8, 1).

Respuesta :

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rarrininger rarrininger · Answer 1 · 2017-03-21T16:10:32+01:00

rarrininger rarrininger

21-03-2017

j+k=3
j-k=7
j-k+k=7+k
j = 7+k

7+k+k=3
7+ 2k = 3
7-7 +2k = 3 -7
2k = -4
2k/2 = -4/2
k = -2

j + -2 = 3
j+ -2 +2 = 3+2
j = 5

Check
5 + -2 = 3
3=3

The solution is (5, −2).

Answer Link

Need help will do anything plzzzzz!! Use the substitution method. {j+k=3 {j-k=7 There are an infinite number of solutions. There is no solution. The solution is (5, −2). The solution is (8, 1).

Respuesta :

Otras preguntas

Need help will do anything plzzzzz!!

Use the substitution method.

{j+k=3
{j-k=7
There are an infinite number of solutions.

There is no solution.

The solution is (5, −2).

The solution is (8, 1).