20-02-2015
Mathematics

contestada

if t is a number greater than 1, then t^2 is how ,much greater than t?

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Аноним Аноним

20-02-2015

[tex] t^{2} -1 >0[/tex]
Therefore, [tex]t(t-1)>0[/tex]

Answer: [tex]t(t-1)[/tex]

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