Answer:
x=29
z=13
<RIG= 59°
<ZIM=31°
(vertically opposite angles)
<ZIA=<MIG
3x-56=x+2
group like terms
3x-x=56+2
2x=58
divide both side by the coefficient of x
2x/2=58/2
<RIG+<GIM=90°
4z+7+x+2=90°
where x=29
4z+7+29+2=90°
4z+38=90°
make for 4z the subject
4z=90°-38°
4z=52°
let z stand alone
4z/4=52/4
<RIG=4z+7
where z=13
4(13)+7
52°=RIGZ
<ZIM=x+2
where x =39+2
x=31°
