emcl07
emcl07 emcl07
  • 17-07-2022
  • Mathematics
contestada

2x - 15 ≤ 5 pls help

Respuesta :

subtomex0
subtomex0 subtomex0
  • 17-07-2022

[tex]2x - 15 \leqslant 5 \\ 2x \leqslant 20 \\ x \leqslant 10[/tex]

Interval Notation: x ε ( -∞ , 10 ]

Answer Link
Ben
Ben Ben
  • 17-07-2022

[tex]\Huge\boxed{x\leq10}[/tex]

To solve for [tex]x[/tex], you need to isolate it on one side of the equation.

Start by adding [tex]15[/tex] to both sides.

[tex]\begin{aligned}2x-15+15&\leq5+15\\2x&\leq20\end{aligned}[/tex]

Now, divide both sides by [tex]2[/tex] for the final answer.

[tex]\begin{aligned}\frac{2x}{2}&\leq\frac{20}{2}\\x&\leq10\end{aligned}[/tex]

Answer Link

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