Respuesta :
The acceleration and time is mathematically given as
a=gsinθ
[tex]t=\frac{2d}{gsinθ}[/tex]
What is the acceleration of the car, assuming the driveway is frictionless, and how long does it take the front bumper to reach the bottom of the hill, and what is the car’s speed as it arrives there?
Generally, the equation for the Force of the car is mathematically given as
[tex]N = mg cos\theta[/tex]
Therefore
[tex]ma=mgsin\theta[/tex]
a=gsinθ
The acceleration of the car is mathematically given as
a=gsinθ
Generally, the equation for the final velocity of the car is mathematically given as
[tex]v^2−u^2=2as[/tex]
Therefore
[tex]v 2 −(0) 2 =2(gsin\theta)d[/tex]
[tex]v= \sqrt {2gsin\theta.d}[/tex]
Generally, the equation for the motion of the car is mathematically given as
v−u=at
[tex]2gsin\thetad =(gsin\theta)t[/tex]
[tex]t=\frac{2d}{gsinθ}[/tex]
In conclusion, the time it takes the front bumper to reach the bottom of the hill is
[tex]t=\frac{2d}{gsinθ}[/tex]
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