City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?

A) City A was 5: C. and City B was 4° C.
B) City À was 3° C, and City B was -1° C
C)City A was 8° C. and City 3 was -3° C.
D)City À was 5° C, and City 3 was -5° C.

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alvinsunnychirayathm alvinsunnychirayathm · Answer 1 · 2022-06-16T18:22:14+02:00

Answer:

A) City A was 5°C and City B was 4°C

Step-by-step explanation:

let temperature of City A be x and City B be y

According to the conditions of the question

4x = 8 + 3y (first temperature)

x - 2y = -3 (second temperature)

x = -3 + 2y

4(x) = (-3 + 2y)×4

4x = -12 + 8y

But it's already given that 4x = 8 + 3y

So,

8 + 3y = -12 + 8y

8 + 12 = 8y - 3y

20 = 5y

y = 20/5

y = 4

That means City B temperature was 4°C

So Option A

If you want you can find x to find City A temperature

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