kadencesimons kadencesimons

16-06-2022
Mathematics

contestada

In parallelogram ABCD , BE=7x−2 and ED=x2−10 .

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Medunno13 Medunno13

23-06-2022

I'm assuming that the diagonals intersect at E. Since diagonals of a parallelogram bisect each other, BE=ED.

7x-2=x²-10
x²-7x-8=0
(x-8)(x+1)=0
x = -1, 8

As distance must be positive, we reject the negative case, so x=8.

Thus, BE=ED=54.

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