emilyR55811 emilyR55811
  • 18-05-2022
  • Mathematics
contestada

What is the solution of startroot x 12 endroot = x?

Respuesta :

profarouk profarouk
  • 18-05-2022

Answer:

x = 0  ;  x = 1

Step-by-step explanation:

[tex]\sqrt{x^{12}} =x[/tex]

[tex]\Longleftrightarrow \sqrt{x^{6\times 2}} =x[/tex]

[tex]\Longleftrightarrow \sqrt{\left( x^{6}\right)^{2} } =x[/tex]

[tex]\Longleftrightarrow |x^{6}|=x[/tex]

[tex]\Longleftrightarrow x^{6}=x\ \ \ ;\ |x^{6}|=x^{6}[/tex]

[tex]\Longleftrightarrow x^{6}-x=0[/tex]

[tex]\Longleftrightarrow x(x^{5}-1)=0[/tex]

[tex]\Longleftrightarrow x=0 \ \ or\ \ (x^{5}-1)=0[/tex]

[tex]\Longleftrightarrow x=0\ \ or\ \ x^{5}=1[/tex]

[tex]\Longleftrightarrow x=0\ \ or\ \ x=1[/tex]

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