Answer:
41.25
Explanation:
I am not sure if your teacher expects you to just find specific heat yourself, but if they do answer it using as below:
Quick search shows aluminium specific heat is 0.90 J/gC.
use formula: q = mcΔT (q = heat, m= mass, c= specific heat, ΔT is temperature change)
q = mcΔT
q/(mc) = ΔT
32.3/(0.87 x 0.90) = ΔT
ΔT = 41.25 C
