Respuesta :

sm70122

Answer:

4 mg

Step-by-step explanation:

Plug in everything that they have given for the equation

since x is the number of half-lives, and iodine-131 has a half-life of 8, and the question is asking for how much there will be left after 32 days, 8 * 4 = 32, so x will be 4.

y = 64(0.5)^4

and solve

y = 4

so there will be 4 mg of iodine-131 left after 32 days.

Answer:

4 mg

Step-by-step explanation:

half- life is 8 days then 32 ÷ 8 = 4 half- lives , then

y = 64 [tex](0.5)^{4}[/tex] = 64 × 0.0625 = 4 mg left

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