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A spring is stretched by 0.02m when a mass of 0.1kg is attached to it. What is
the spring constant? (Show working pleaaase)

Respuesta :

Answer:

5

Explanation:

hookes law, f=kx

the force which is the mass,0.1, is equal to the constant multiplied by thd extension,0.02, so

0.1= f×0.02

0.1/0.02=5

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