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  • 20-02-2022
  • Mathematics
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[tex]\sqrt{2x^{2} -1} \geq 1-x[/tex]

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secondbreakfest
secondbreakfest secondbreakfest
  • 20-02-2022

Answer:

[tex]x\geq 2[/tex]

Step-by-step explanation:

by squaring both sides:

[tex]2x^2 - 1 \geq x^2 + 2x - 1[/tex]

canceling out 1

[tex]2x^2 \geq x^2 + 2x[/tex]

subtract x^2 on both sides

[tex]x^2\geq 2x[/tex]

divide by x on both sides

[tex]x\geq 2[/tex]

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