lucyshannon
lucyshannon
17-01-2017
Mathematics
contestada
calculate y'. xy^4+x^2y=x+3y
Respuesta :
alekos
alekos
17-01-2017
y^4 + 4xy^3 (y') + 2xy + x^2 (y') = 1 + 3 (y')
(y')(4xy^3 + x^2 - 3) = 1 -y^4 -2xy
I'll let you do the next line
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