yessir2524 yessir2524
  • 21-01-2022
  • Mathematics
contestada

6, -12, 24, 8th term of geometric sequence

Respuesta :

jimrgrant1 jimrgrant1
  • 21-01-2022

Answer:

a₈ = - 768

Step-by-step explanation:

The nth term of a geometric sequence is

[tex]a_{n} [/tex] = a₁ [tex](r)^{n-1} [/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = [tex]\frac{a_{2} }{a_{1} } [/tex] = [tex]\frac{-12}{6} [/tex] = - 2 , then

a₈ = 6 × [tex]-2)^{7} [/tex] = - 6 × - 128 = - 768

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