Hey there mate ;)
Let the smaller number be 'x'
Let the larger number be 'x+6'
Given sum =50
Now by ordering them in position,
[tex]x + x + 6 = 50[/tex]
[tex] = > 2x + 6 = 50[/tex]
[tex] = > 2x = 50 - 6[/tex]
[tex] = > 2x = 44[/tex]
[tex] = > x = \frac{44}{2} [/tex]
[tex] = > x = 22[/tex]
So, the smaller number is 22, therefore the larger number is :-
[tex]x + 6[/tex]
[tex] = > (22) + 6[/tex]
[tex] = > 28[/tex]
