ethanrosen ethanrosen
  • 20-12-2021
  • Mathematics
contestada

Find the equation of the normal to the curve in y=mx+b format : p(t) = 3t^2 - 8t + 3 at t = 3

Respuesta :

goddessboi goddessboi
  • 20-12-2021

Answer:

[tex]y=10x+24[/tex]

Step-by-step explanation:

Find the derivative of the function

[tex]p'(t)=\frac{d[p(t)]}{dt}=\frac{d}{dt}(3t^2-8t+3)=6t-8[/tex]

Determine the slope of p(t) at t=3:

[tex]p'(3)=6(3)-8=18-8=10[/tex]

Find p(3):

[tex]p(3)=3(3)^2-8(3)+3=3(9)-24+3=27-21=6[/tex]

Determine y-intercept:

[tex]y=mx+b[/tex]

[tex]6=10(3)+b[/tex]

[tex]6=30+b[/tex]

[tex]-24=b[/tex]

Final equation:

[tex]y=10x-24[/tex]

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