[tex]\huge \bf༆ Answer ༄[/tex]
Let the number be x
According to the given question, the expression will be ~
- [tex] \sf3x - 3 = \dfrac{5}{6} [/tex]
- [tex] \sf3x = \dfrac{5}{6} + 3[/tex]
- [tex] \sf3x = \dfrac{5 + 18}{6} [/tex]
- [tex] \sf3x = \dfrac{23}{6} [/tex]
- [tex] \sf x = \dfrac{23}{6} \times \dfrac{1}{ 3} [/tex]
- [tex] \sf{x} = \dfrac{23}{18} [/tex]
The required number is ~
- [tex] \boxed{ \sf \dfrac{23}{18} }[/tex]
