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  • 18-09-2021
  • Mathematics
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Given f(x)=2x^2-3x+1, determine the value of 3f(-2x)

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tewodroshabtamu29
tewodroshabtamu29 tewodroshabtamu29
  • 18-09-2021

Answer:

Step-by-step explanation:

3f(-2x)= 3[2(-2x)^2-3(-2x)+1]

         =3[2(4x^2)+6x+1]

         =3[8x^2+6x+1]

         =24x^2+18x+3

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