Respuesta :

Mass is not required

  • Force=F=20N
  • Angle=30°
  • Displacement=s=5m

[tex]\\ \rm\longmapsto W=Fscos\Theta[/tex]

[tex]\\ \rm\longmapsto W=20(5)cos30[/tex]

[tex]\\ \rm\longmapsto W=100\times \dfrac{\sqrt{3}}{2}[/tex]

[tex]\\ \rm\longmapsto W=50\sqrt{3}J[/tex]

spammingallowed

Answer:

[tex]we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 \times 5 \times \cos(30) \\ 100 \cos(30) \\ = 100 \frac{ \sqrt{3} }{2} \\ = 50 \sqrt{3} \\ = 86.6 \: joule\\ thank \: yo[/tex]

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