Answer: p=1
Step-by-step explanation:
[tex]p^{2}+16p-17=0\\p^{2}+16p=17\\1^{2}+16(1)=17\\1+16=17\\p=1[/tex]
(p-1)(p+16)
Also, here's the cross method in completing the square that I tried in the file attachment. I haven't done this in a while, so this may not be neat.
