roki999 roki999
  • 18-06-2021
  • Mathematics
contestada

Помогите пожалуйста
y= sinx/cosx ; y=?

Помогите пожалуйста y sinxcosx y class=

Respuesta :

evgeniylevi
evgeniylevi evgeniylevi
  • 18-06-2021

Answer:

[tex]\frac{1}{cos^2x}[/tex]

Step-by-step explanation:

[tex]y'=\frac{(sinx)'*cosx-(cosx)'*sinx}{cos^2x}=\frac{1}{cos^2x}.[/tex]

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