gladys1232 gladys1232

17-04-2021
Mathematics

contestada

16ef³÷8e²f=
24m²n³
_=
2mn

2k³+k
_=
4k

Respuesta :

gayanepoghosyan gayanepoghosyan

18-04-2021

Answer:

Answer is below

Step-by-step explanation:

16ef³÷8e²f=[tex]\frac{2f^{2}}{e}[/tex]

[tex]\frac{24m^{2} n^{3} }{2mn} = 12m n^{2}[/tex]

[tex]\frac{2k^{3} +k}{4k} =\frac{1}{2} k^{2} +\frac{1}{4}[/tex]

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