lim x approaches infinity of (Square root of x^2 +2)/ x-1 ...?

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19-11-2016
Mathematics

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lim x approaches infinity of (Square root of x^2 +2)/ x-1 ...?

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Nirina7 Nirina7 · Answer 1 · 2016-11-21T14:52:41+01:00

Nirina7 Nirina7

21-11-2016

the answer is
lim sqrt (x^2 +2) /x - 1 = lim sqrt [x^2(1 +2 / x^2) /x - 1 =
lim x sqrt [(1 +2 / x^2) / x(1 - 1/x)= lim sqrt [(1 +2 / x^2) / (1 - 1/x)
and when x approaches infinity we have
lim sqrt (x^2 +2) /x - 1 = sqrt [(1 +0 ) / (1 - 0) = 1/1 = 1

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