Answer:
[tex]\huge\boxed{1) 2n^2-9n}[/tex]
[tex]\huge\boxed{2) 6c\³ + 4c\²}[/tex]
Step-by-step explanation:
Part 1:
= n(n-4)-n(5-n)
By distributive property
= n² - 4n - 5n + n²
= 2n² - 4n - 5n
= 2n² - 9n
Part 2:
= 4c(3c-c²)-2c²(4-5c)
Distributing brackets
= 12c² - 4c³ - 8c² + 10c³
Combining like terms
= 12c² - 8c² - 4c³ + 10c³
= 4c² + 6c³
= 6c³ + 4c²
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
