[tex] \huge \colorbox{pink}{Question } [/tex]
solve this system using substitution x+5y=-32 y=3x
Substitute 3x for y in x + 5y = - 32
[tex]x + 5y = - 32 \\ x + 5(3x) = - 32 \\ x + 15x = - 32 \\ 16x = - 32 \\ \frac{16x}{16} = \frac{ - 32}{16} \\ x = - 2[/tex]
Substitute - 2 for for x in y = 3x
[tex]y = 3x \\ y = 3( - 2) \\ y = - 6[/tex]
[tex] \huge \colorbox{pink}{Answer} [/tex]
x = - 2
y = - 6
Hope it helps ^_^
