19-03-2021
Chemistry

contestada

how much heat is released as 5.00G of PB cool from 75.0° C to 25.0° C

Respuesta :

lawalj99 lawalj99

24-03-2021

Answer:

32.25 J

Explanation:

Heat, H = ?

Mass, m = 5g = 5 / 1000 = 0.005 Kg

Initial Temperature = 75.0° C

Final Temperature = 25.0° C

Temperature change, ΔT = Final - Initial = 50° C

Specific heat capacity of lead, C = 129 (J/kg°C)

The relationship between these quantities is given by the equation

H = mCΔT

H = 0.005 * 129 * 50

H = 32.25 J

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