trenedymilburn03 trenedymilburn03
  • 19-03-2021
  • Mathematics
contestada

if p(x)=x*2-1 and q(x)=5(x-1),which expression is equivalent to (p-q)(x)?

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 24-03-2021

Answer:

[tex](p - q)(x) = (x -1) (x - 4)[/tex]

Step-by-step explanation:

Given

[tex]p(x) = x^2 - 1[/tex]

[tex]q(x) = 5(x - 1)[/tex]

Required

(p - q)(x)

This is represented as:

[tex](p - q)(x) = p(x) - q(x)[/tex]

[tex](p - q)(x) = x^2 - 1 - 5(x - 1)[/tex]

[tex](p - q)(x) = x^2 - 1 - 5x + 5[/tex]

Collec like terms

[tex](p - q)(x) = x^2 - 5x + 5 - 1[/tex]

[tex](p - q)(x) = x^2 - 5x + 4[/tex]

Expand

[tex](p - q)(x) = x^2 -4x - x + 4[/tex]

Factorize

[tex](p - q)(x) = x(x -4) - 1(x - 4)[/tex]

[tex](p - q)(x) = (x -1) (x - 4)[/tex]

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