Answer:
Perimeter of trapezoid = 25.66 cm
Step-by-step explanation:
Trapezoid ABCD contains two triangles ΔABF, ΔCDE and a square with side length 4 cm.
By applying Pythagoras theorem in ΔABF,
AB² = BF² + AF²
AB² = 4² + 3²
AB = [tex]\sqrt{16+9}[/tex]
AB = 5 cm
Similarly, By applying Pythagoras theorem in ΔCDE,
CD² = DE² + CE²
CD² = 4² + 4²
CD = [tex]\sqrt{32}[/tex]
CD =5.66 cm
Perimeter of the given trapezoid = AB + BC + CD + AD
= 5 + 4 + 5.66 + (3 + 4 + 4)
= 25.66 cm
