olejcuello olejcuello
  • 17-03-2021
  • Mathematics
contestada

Prove that for all integers a and b. If
a^2(b^2 - 2b) is odd, then a and b are odd​

Respuesta :

Аноним Аноним
  • 17-03-2021

Answer:

  • we have:

a²(b² - 2b) = a²b² - 2a²b

  • a²(b² - 2b) is odd but -2a²b is the even number

=> a²b² must be the odd (because an odd number minus an even number equals an odd number)

=> a and b are odd (proven)

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