Answer:
[tex]l=16(b-1.25)[/tex]
Step-by-step explanation:
Given that,
The area of the field is [tex]16b^2+60b-100[/tex]
One dimensions = (b+5)
The field is in the shape of a rectangle whose are is given by :
A = lb
Wher
l is the length or the other dimension
[tex]l=\dfrac{A}{b}\\\\l=\dfrac{16b^2+60b-100}{b+5}\\\\l=\dfrac{(16(b+5)(b-1.25)}{b+5}\\\\l=16(b-1.25)[/tex]
So, the other dimension be [tex]16(b-1.25)[/tex].
