Answer:
The deceleration of the plane is 0.25 m/[tex]s^{2}[/tex].
Explanation:
Deceleration is the converse of acceleration.
From first law of motion, we have;
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
Thus,
v = 50 m/s
u = 80 m/s
t = 120 s
50 = 80 + 120a
50 - 80 = 120a
-30 = 120a
a = [tex]\frac{-30}{120}[/tex]
= -0.25
a = -0.25 m/[tex]s^{2}[/tex]
The deceleration of the plane is 0.25 m/[tex]s^{2}[/tex].
