Answer:
5.91 kN
Explanation:
The schematic view of the free body diagram of the car is shown in the image attached below.
Let's first calculate the weight of the car.
W = mg
W = 1360 × 9.81
W = 13341.6 N
W = 13.3416 kN
From the image, Using the equilibrium equations, we have:
[tex]\sum F_x = 0\\[/tex]
T cos (18° - 10°) - 13.3416 sin 26° = 0
T cos 8° - 5.84857 = 0
T cos 8° = 5.84857
[tex]T = \dfrac{5.84857}{cos \ 8^0}[/tex]
[tex]T = \dfrac{5.84857}{0.9903}[/tex]
T = 5.905856811 N
T ≅ 5.91 kN
